Asked by Sara

log (3x-9) = 2log3 - log27+ log(x+3)

Solving the euqation using the properties of logarithms

How do you do this?

Answers

Answered by drwls
I will assume that all logs have the same base.

log(3x -9) = log [3^2*(x+3)/(3^3]
= log[(x+3)/3]

Therefore
3x -9 = (x+3)/3
9x -27 = x +3
8x = 30
x = 3.75

Check:
log (3x -9) = log 2.25 = 0.35218

2log3 -log27 + log(6.75)
= 0.95424 -1.43136 + 0.82930
= 0.35218

It makes no difference what log base you choose, as long as it is the same for all terms. (I chose base 10 when checking)
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions