Asked by lame
1. Solve for x:log27 5x-log27(x+2)=2/3
Answers
Answered by
mathhelper
log27 5x-log27(x+2)=2/3
assuming you have base 27 in your log
then:
log<sub>27</sub> (5x/(x+2)) = 2/3 , where x > 0 by the definition for logs
5x/(x+2) = 27^(2/3)
5x/(x+2) = 9
9x + 18 = 5x
4x = -18
x = -9/2 , but x > 0
so there is no solution.
assuming you have base 27 in your log
then:
log<sub>27</sub> (5x/(x+2)) = 2/3 , where x > 0 by the definition for logs
5x/(x+2) = 27^(2/3)
5x/(x+2) = 9
9x + 18 = 5x
4x = -18
x = -9/2 , but x > 0
so there is no solution.
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