Asked by Gabi
2log3+log300-log9
Answers
Answered by
oobleck
that would be log(3^2 * 300 / 9) = log(2700/9) = log300
In base 10 logs, that would be 2+log3
or, since 2log3 = log(3^2) = log9, you have
log9 + log300 - log9 = log300
In base 10 logs, that would be 2+log3
or, since 2log3 = log(3^2) = log9, you have
log9 + log300 - log9 = log300
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