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2log3+log300-log9
2log3+log300-log9
1 answer
asked by
Gabi
633 views
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
1 answer
asked by
Joe
800 views
using logarithms to solve exponential equations.
5^1+x = 2^1-x I need exact numbers. I did one on my own already. 5^x-1 = 9 5^x-1
4 answers
asked by
Joe
694 views
(I have two questions)
1. Solve for x without a calculator: log3(x^2)=2log3(4)-4log3(5) This is what I have so far:
1 answer
asked by
Moe
737 views
A)If logx=0.25, what is logx4? Rewrite using the power rule, then evaluate. (1 point)
$$ Question 2 A) Which of the following is
1 answer
28 views
A)If logx=0.25, what is logx4? Rewrite using the power rule, then evaluate. (1 point)
$$ Question 2 A) Which of the following is
1 answer
34 views
A)If logx=0.25, what is logx4? Rewrite using the power rule, then evaluate. (1 point)
$$ Question 2 A) Which of the following is
1 answer
36 views
Algebraically determine the value(s) of x: log9(x-5)=1-log9(x+3)
Please help me. Thanks!
1 answer
asked by
Hannah
404 views
Logarithms
3^x-2=18 Work log(3^x-2)=log18 (x-2)log3=log18 xlog3-2log3=log18 x=log3/(log9-log18) e^3x+1=10 lne^3x+1=ln10 3x+1=ln10
1 answer
asked by
jackson
914 views
Evaluate log9 162 - log9 (2/3)
3 answers
asked by
Raven
129 views