Question
The density of gold is 19.3 x 10^3 kg/m^3. What buoyant force does a .6 kg gold crown experience when it is immersed in water?
Answers
drwls
Buoyant force = (Water density) x (gold volume)x g
The volume of the gold is
(mass)/(gold density)= 3.11*10^-5 m^3
The density of water is 1000 kg/m^3
The answer will be in Newtons after multiplying by g.
This is obviously not a tooth crown - At 0.6 kg, it would weigh 19 oz. and cost %26,000 at today's prices
The volume of the gold is
(mass)/(gold density)= 3.11*10^-5 m^3
The density of water is 1000 kg/m^3
The answer will be in Newtons after multiplying by g.
This is obviously not a tooth crown - At 0.6 kg, it would weigh 19 oz. and cost %26,000 at today's prices