Asked by Beth
Calculate the pH of each of the following solutions.
(a) [H3O+] = 2.9 10-10 M- I got 9.5 but its wrong. I used the equation pH= -log[H3O+] Is this the wrong equation?
(b) [H3O+] = 6.4 10-2 M
thanks:)
(a) [H3O+] = 2.9 10-10 M- I got 9.5 but its wrong. I used the equation pH= -log[H3O+] Is this the wrong equation?
(b) [H3O+] = 6.4 10-2 M
thanks:)
Answers
Answered by
DrBob222
I think you are doing it correctly. I think you are just reading the calculator wrong (or ignoring the other digits).
pH = -log(H^+) = -log(2.9E-10) = -(-9.5376) = 9.5376 which rounds to 2 significant figures as 9.54. I suspect you are keying your answer into a data base and 9.5 is not right but 9.54 is. I think 9.5376 will be counted wrong, also.
pH = -log(H^+) = -log(2.9E-10) = -(-9.5376) = 9.5376 which rounds to 2 significant figures as 9.54. I suspect you are keying your answer into a data base and 9.5 is not right but 9.54 is. I think 9.5376 will be counted wrong, also.
Answered by
Beth
Oh ok, thanks!
Answered by
Lizu Mali
Calculate the pH for each of the following solutions at 25 °C.[H³O+] = 1.3 x 10-10 M
pH = -log [H³O]
= -log (13* 10 ^-10)
= 8.89
pH = -log [H³O]
= -log (13* 10 ^-10)
= 8.89
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