Asked by Shirley
algebra, write a quadratic equation in the variable x having the given numbers as solutions -ã10, 6ã10
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Answered by
Anonymous
If -ã10, 6ã10 mean x1=-10 and x2=10 in this case you equatin is:
y=(x-x1)*(x-x2)
y=[x-(-10)]*(x-10)
y=a*(x+10)*(x-10)
y=(x^2+10x-10x-100)
y=x^2-100
y=(x-x1)*(x-x2)
y=[x-(-10)]*(x-10)
y=a*(x+10)*(x-10)
y=(x^2+10x-10x-100)
y=x^2-100
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