Asked by holiday
use backtracking to solve each e
quations ?.
2x
+1=9, 7k-3=32, 5(n-8)=25 2(2t-1)=14
8x-1=63 ,2x-5=15,
quations ?.
2x
+1=9, 7k-3=32, 5(n-8)=25 2(2t-1)=14
8x-1=63 ,2x-5=15,
Answers
Answered by
JJ
Okay so
2x+1=9
We move the 1 over to the other side of the equal sign, which means the equation now reads
2x=9-1
solve this
2x=8
now we divide both sides by 2 (its the multiplier of x and we want to split them apart)
x=4
TaDa!
With your brakets
2(2t-1)= 14
Okay so firstly we divide both sides by 2
t-0.5 = 7
Then we move the 0.5 over the equal sign
t = 7 + 0.5
t = 7.5
TaDa
Now if you do the rest of your equations they should work.
Hope this helps
:)
ps> I'm not a teacher so you should probably check with a math teacher as well.
2x+1=9
We move the 1 over to the other side of the equal sign, which means the equation now reads
2x=9-1
solve this
2x=8
now we divide both sides by 2 (its the multiplier of x and we want to split them apart)
x=4
TaDa!
With your brakets
2(2t-1)= 14
Okay so firstly we divide both sides by 2
t-0.5 = 7
Then we move the 0.5 over the equal sign
t = 7 + 0.5
t = 7.5
TaDa
Now if you do the rest of your equations they should work.
Hope this helps
:)
ps> I'm not a teacher so you should probably check with a math teacher as well.
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