2sin^2x+3sinx+1

Find the area between y=3sinx and y=3cosx over the interval [0,pi].

Solve for x: 2sin^2x = 3sinx + 2 on -pi < x < 4pi (the "<" signs are less than or equal to) i g...

2sin^2x-3sinx=-1 sin^2x-3sinx=-1/2 times -3 sq. root of (sin^2x)+sinx= sq. root of 3/sq. root...

2cos^2x-3sinx=0

How do you solve? 3-3sinx-2cos^2(x) = 0

Show that the equation x+3sinx=2 has a root between 0.4 and 0.6.express the root to four significant...

Show that the equation;x+3sinx=2 has a root between x=0.4 and x=0.6 using newton raphson's formular...

d^2y/dx^2+4dy/dx+4y=4cosx+3sinx

integrate from 0 to pi/2 (3sinxcosx)/(1+3sin^2x)^1/2

int dx/3sinx+4cosx dx =

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