Question

2cos^2x-3sinx=0

Answer 1

2(1 - sin^2x) - 3sinx = 0
-2sin^2x - 3sinx + 2 = 0
2sin^2x + 3sinx - 2 = 0
(2sinx -1)(sinx + 2) = 0
sinx = 1/2 or sinx = -2
x = 30° or 150° or (sinx = -2 has no solution)

x = 30 or 150 ° which is also π/6 or 5π/6 radians

Answer 2

Thanks