Asked by Frank
integrate from 0 to pi/2 (3sinxcosx)/(1+3sin^2x)^1/2
Answers
Answered by
Steve
note that if
u = 1+3sin^2x
du = 6sinxcosx
so you have
∫[1,4] u^(-1/2) 1/2 du
= √u [1,4]
= 1
u = 1+3sin^2x
du = 6sinxcosx
so you have
∫[1,4] u^(-1/2) 1/2 du
= √u [1,4]
= 1
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