Asked by cr
                A 10.0 kg box is pulled along a horizontal surface by a 40N force which is applied at a 30.0 degree angle. If uk = 0.3, calculate the acceleration of the box. 
            
            
        Answers
                    Answered by
            drwls
            
    a = Fnet/M
Fnet is the net force in the direction of motion
Fnet = 40N*cos30 - M*g*uk
a = (40/10)*cos30 -g*0.3
= 3.464 - 2.940 = _____ m/s^2
    
Fnet is the net force in the direction of motion
Fnet = 40N*cos30 - M*g*uk
a = (40/10)*cos30 -g*0.3
= 3.464 - 2.940 = _____ m/s^2
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