Asked by Aishah
Consider the box being pulled across the horizontal surface again. If the box has a mass of 10kg, the coefficient of friction is 0.25,the distance that the box is pulled is 5m, the force is 150N and the angle is 30 degrees, ehat was the initial speed of the box if the final speed is 12m/sec ?
Answers
Answered by
bobpursley
Initial energy + work putin=finalenergy+friction
1/2 m vi^2 + 150*cos30*5=1/2 m 12^2 + .25(10g+150sin30)10
solve for vi
1/2 m vi^2 + 150*cos30*5=1/2 m 12^2 + .25(10g+150sin30)10
solve for vi
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.