Asked by mustafa

A 10-kg box is pulled along a horizontal surface by a
force of 40N applied at a 30° angle above
horizontal. The coefficient of kinetic friction is 0.3.
Calculate the acceleration.
Answered by Henry
Wb = M*g = 10 * 9.8 = 98 N.

Fn = 98-40*sin30 = Normal force.

Fk = u*Fn = Force of kinetic friction.

a = (Fap*Cos30-Fk)/M.

Answered by Misheck
A box of mass 10kg is at rest on a horizontal plane.A force of 20N is applied to it at 30 degrees to the plane.assuming the is no frictional force between the box and the plane,calculate the acceleration of the box.
Answered by Anonymous
2m/s
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