Question

heating an ore of antimony sulfide in the presence of iron gives th element antimony and iron(2) sulfide. when 15.0 antimony sulfide reacts with an excess of iron, 9.84 g antimony is produced. what is the percent yield of this reaction?

Answer 1

You need to calculate the theoretical yield (Y) starting from 15.0 (I presume g) of antimony sulfide. In order to do this you need a balanced equation, so you need to insert symbols and balance:

iron + antimony sulfide -> antimony + iron(II)sulfide.

To calculate the theoretical yield find the number of moles of antimony sulfide in 15.0 g.

15.0 g/(Molar mass of antimony sulfide)

then calculate the theoretical number of moles of antimony formed using the balanced equation.

Y (theoretical yield) is then

Y=moles of antimony x molar mass of antimony.

percentage yield
= (9.84 g x 100)/Y