Question
40g of antimony combine with 80g of oxygen to form an oxide of antimony what is the simplest formula of the oxide
Answers
Devron
40 g of Sb*(1 mole/121.76 g)= moles of Sb=0.329
80 g of O * (1 mole/16.0 g)= moles of O=5
divide lowest moles by the other
Sb=0.329/0.329=1
O=5/0.329=15
SbO15
Do not think that this is even possible to synthesize!!!!
80 g of O * (1 mole/16.0 g)= moles of O=5
divide lowest moles by the other
Sb=0.329/0.329=1
O=5/0.329=15
SbO15
Do not think that this is even possible to synthesize!!!!