Asked by GODBLESS

40g of antimony combine with 80g of oxygen to form an oxide of antimony what is the simplest formula of the oxide

Answers

Answered by Devron
40 g of Sb*(1 mole/121.76 g)= moles of Sb=0.329

80 g of O * (1 mole/16.0 g)= moles of O=5

divide lowest moles by the other


Sb=0.329/0.329=1

O=5/0.329=15



SbO15


Do not think that this is even possible to synthesize!!!!
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