Asked by anon
. Antimony pentachloride decomposes according to the following equation.
SbCl5 (g) → SbCl3 (g) + Cl2 (g)
Suppose that 10.0 g of antimony pentachloride is placed in a 5.00 L container and allowed to establish equilibrium. Calculate the concentration of all species at equilibrium.
K = 2.51 x 10-2
SbCl5 (g) → SbCl3 (g) + Cl2 (g)
Suppose that 10.0 g of antimony pentachloride is placed in a 5.00 L container and allowed to establish equilibrium. Calculate the concentration of all species at equilibrium.
K = 2.51 x 10-2
Answers
Answered by
DrBob222
mols SbCl5 = grams/molar mass = ?
M = mols/5.0L = approx 0.007 but that's an estimate.
............SbCl5 ==> SbCl3 + Cl2
I...........0.007.......0......0
C............-x.........x......x
E..........0.007-x......x......x
Substitute the E line into the Keq expresson and solve for x, then evaluate the other terms.
M = mols/5.0L = approx 0.007 but that's an estimate.
............SbCl5 ==> SbCl3 + Cl2
I...........0.007.......0......0
C............-x.........x......x
E..........0.007-x......x......x
Substitute the E line into the Keq expresson and solve for x, then evaluate the other terms.
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