Asked by lyla
A satellite circling the earth has an average power consumption of 370.0 W. Assuming 5.4% efficiency for conversion of solar energy to electrical energy, what area is required for the solar panels?
Answers
Answered by
drwls
The solar irradiance at the earth's distance is about H = 1366 W/m^2.
To generate 370 W of electricity with 5.4% efficiency, you need an area A such that:
1366 W/m^2*(0.054)*A = 370 Watts
Solve for A, in square meters. The panels will have to always face the sun
To generate 370 W of electricity with 5.4% efficiency, you need an area A such that:
1366 W/m^2*(0.054)*A = 370 Watts
Solve for A, in square meters. The panels will have to always face the sun
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