Question
an earth satellite in circular orbit 1250 kilometers high makes one complete revolution evry 90 min. What is it linear speed? use 6400 kilometers for the radius of the earth.
Answers
Anonymous
the diameter of the orbit is 1250+6400 km
the distance it goes in 90 minutes is therefore
pi*(1250+6400) km
the speed is distance over time
pi*(1250+6400)/90 km/hr
the distance it goes in 90 minutes is therefore
pi*(1250+6400) km
the speed is distance over time
pi*(1250+6400)/90 km/hr
gab
okay but don't you have to multiply the (1250+6400) by pi and 2 then divide that by 90? i got 534.07 as an answer
Anonymous
Yes, sorry, I left the 2 out. circumference = 2 pi R
gab
thank you!
Reiny
the radius at which it rotates = 6400+1250
circumference = 2pi(r)
= 2(6400+1250)pi = 15300pi
rate = distance/time
= 15300pi/1.5 km/h
= 32044 km/hr
circumference = 2pi(r)
= 2(6400+1250)pi = 15300pi
rate = distance/time
= 15300pi/1.5 km/h
= 32044 km/hr