Question

A spy satellite is in circular orbit around Earth. It makes one revolution in 6.01 hours.
how high above earth?
acceleration?
bobpursley
change time to seconds for the period.

v=2PI h/period
v^2=(2PI)^2/period^2

v^2/r= 9.8*(re^2/r^2) where r is the orbital radius.

solve for r, then altitude is r-re.

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