Asked by Steve
Body A of mass M has an original velocity of 6.2 m/s in the +x-direction toward a stationary body (body B) of the same mass. After the collision, body A has velocity components of 1.1 m/s in the +x-direction and 2.2 m/s in the +y-direction. What is the magnitude of body B's velocity after the collision?
Answers
Answered by
drwls
Momentum must be conserved.
Let M be the mass of either A or B.
The total momentum in the y direction must remain zero, therefore
Vyb(final) = -2.2 m/s
In the x-direction,
6.2 M = 1.1 M + M*Vyx(final)
Vyb(final) = 5.1
Get the magnitude and direction from those components.
Let M be the mass of either A or B.
The total momentum in the y direction must remain zero, therefore
Vyb(final) = -2.2 m/s
In the x-direction,
6.2 M = 1.1 M + M*Vyx(final)
Vyb(final) = 5.1
Get the magnitude and direction from those components.
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