Asked by Ariannah
A one-liter container completely filled with mercury has a mass of 13.6 kg and weighs 133.3 N. What is the buoyant force on the container if the container is placed in water?
Answers
Answered by
bobpursley
We will be happy to critique your thinking, but not do it for you.
Answered by
eliana
9.86N
Answered by
Alexander
Given:
Volume of container = 1 L = 1000 cm3
= 1 x 103
cm3
since 1 m = 100 cm
then 1 m3
= 1,000,000 cm3
= 1 x 106
cm3
thus 1 L = 1 x 10-3 m3
density of water = 1 x 103
kg/m3
Solution:
Volume of container = volume of water displaced = 1 x 10-6 m3
Weight of water displaced (Ww) = volume of water displaced (Vw) x density of water (ρw)
Ww = Vwρw
= 1 x 10-3 m3
x 1 x 103
kg/m3
= 1 kg
but 1 kg = 9.8 N
therefore Ww = 9.8 N
Volume of container = 1 L = 1000 cm3
= 1 x 103
cm3
since 1 m = 100 cm
then 1 m3
= 1,000,000 cm3
= 1 x 106
cm3
thus 1 L = 1 x 10-3 m3
density of water = 1 x 103
kg/m3
Solution:
Volume of container = volume of water displaced = 1 x 10-6 m3
Weight of water displaced (Ww) = volume of water displaced (Vw) x density of water (ρw)
Ww = Vwρw
= 1 x 10-3 m3
x 1 x 103
kg/m3
= 1 kg
but 1 kg = 9.8 N
therefore Ww = 9.8 N
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