Asked by Lavern
please help
Factor completely
144b^2+648bg+729g^2
Factor completely
144b^2+648bg+729g^2
Answers
Answered by
Reiny
start by pecking away common factors
144b^2+648bg+729g^2
= 9(16b^2 + 72bg + 81g^2)
ahh, looks like perfect squares at front and back
could (4b + 9g)^2 give us a middle term of 72 bg ??
2(4)(9) = 72 , yeaaaahhh!
= 9(4b+9g)^2
144b^2+648bg+729g^2
= 9(16b^2 + 72bg + 81g^2)
ahh, looks like perfect squares at front and back
could (4b + 9g)^2 give us a middle term of 72 bg ??
2(4)(9) = 72 , yeaaaahhh!
= 9(4b+9g)^2
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