The gun, mount, and train car had a total mass of 1.22 106 kg. The gun fired a projectile that was 80.0 cm in diameter and weighed 7502 kg. In the firing illustrated in the figure, the gun has been elevated at è = 18.0° above the horizontal. If the railway gun was at rest before firing and moved to the right at a speed v = 4.53 m/s immediately after firing, what was the speed of the projectile as it left the barrel (muzzle velocity)?
2 answers
it is not clear to me the figure, but conservation of momentum in the horizontal direction will work this out.
Use the equation M1V1=M2V2 where M1V1 is the momentum of the rail gun and M2V2 is the mass of the bullet and the horizontal component of its speed.