Asked by Bob
Climbing to the top of Mount Everest is hard. But, it's slightly easier than you might think as people weigh less as they climb to the top. Let WE be a person's weight on top of Mount Everest and WS be their weight at sea level. What is the value of 1−WE/WS?
Details and assumptions:
+ Assume the earth (other than Everest) is a sphere of mass 6×1024 kg and radius 6,370 km.
+ The top of Mount Everest is 8,848 m above the surface of the earth.
Details and assumptions:
+ Assume the earth (other than Everest) is a sphere of mass 6×1024 kg and radius 6,370 km.
+ The top of Mount Everest is 8,848 m above the surface of the earth.
Answers
Answered by
drwls
Weight is inversely proportional to the square of the distance from the center of the Earth.
WE/WS = [6370/(6370+8.85)]^2
= 0.9972
1 - (WE/WS) = 2.77*10^-3
0.27% of the person's weight is "lost" at the summit of Everest.
WE/WS = [6370/(6370+8.85)]^2
= 0.9972
1 - (WE/WS) = 2.77*10^-3
0.27% of the person's weight is "lost" at the summit of Everest.
Answered by
Mathsfreak
Still a simple careless mistake :
1-9972=0.0028 nt 27.:)
1-9972=0.0028 nt 27.:)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.