Question
For safety in climbing, a mountaineer uses a nylon rope that is 50m long and 1.0cm in diameter. When supporting a 90kg climber, the rope elongates 1.6m. Find its Young's modulus
This is what I have so far, I am getting the wrong answer. Can you please fix my mistake? (Studying for an exam)
Lo=50m
diameter=1.0cm or .01m, meaning radius is .005m
mass=90kg or 882N
delta L=1.6m
Y=?
F/A= Y (delta L/ Lo)
882N/1.57= Y (1.6m/50m)
Y= 17555.73 is my answer. Correct answer is 3.5x10^8 Pa.
Perhaps I am not calculating the area right?
The formula that I used is 2pi r^2 +2pi r +h
This is what I have so far, I am getting the wrong answer. Can you please fix my mistake? (Studying for an exam)
Lo=50m
diameter=1.0cm or .01m, meaning radius is .005m
mass=90kg or 882N
delta L=1.6m
Y=?
F/A= Y (delta L/ Lo)
882N/1.57= Y (1.6m/50m)
Y= 17555.73 is my answer. Correct answer is 3.5x10^8 Pa.
Perhaps I am not calculating the area right?
The formula that I used is 2pi r^2 +2pi r +h
Answers
the area is pie r^2 then you'll get the answer