To keep the block from sliding downhill the block uphill, the applied force must exceed
Fmin = M*g*sin44.6 - M*g*cos44.6 * 0.540
That is the component of weight down the hill, minus the maximum possible friction force
A block with a mass of 3.07 kg is placed at rest on a surface inclined at an angle of 44.6° above the horizontal. The coefficient of static friction between the block and the surface is 0.540, and a force of magnitude pushes upward on the block, parallel to the inclined surface. The block will remain at rest only if is greater than a minimum value, Fmin, and less than a maximum value, Fmax. Calculate Fmin.
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