Asked by Era

The block has mass m=8.5 kg and lies on a fixed smooth frictionless plane tilted at an angle theta=20.0 degrees to the horizontal.

Determine the acceleration of the block as it slides down the plane.

If the block starts from rest 15.0 m up the plane from its base, what will be the block's speed when it reaches the bottom of the incline? Caption: Block on inclined plane.
Answered by dfasdffas
do the damn problem noob
Answered by Acceleration across the slope: mg sin theta, that is.. Assuming that there is no friction.. 9.8 m/s
Acceleration across the slope: mg sin theta, that is.. Assuming that there is no friction.. 9.8 m/s^2 X sin 20 = 3.35 m/s^s

PE = mgh;
KE = 1/2 X mv^2;
mgh= 1/2 X mv^2;
v = sqrt(2gh);
v = sqrt (294);
v = 17.1 m/s
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