Question

A block of mass M1 = 15 kg is lying on a horizontal friction-less surface is connected to a
string passing over a friction-less pulley. A mass of M2 = 25 kg is hanging at its other end as
shown in the figure below.
(i) Find the acceleration in the masses.
(ii) What is the tension in the cord that connects the two masses?
(iii) How far will m2 fall in time 2s after the system is released?

Answer 1

system force= 25*9.8

system mass=40kg

Force=mass*acceleration.

Tension= massbeingmoved*a=15*a

distance=1/2 a t^2