Asked by knswimmerkat
How do I prepare 80 mL of 0.10 M HC2H3O2 from a 6.0 M solution of Acetic acid?
How do I prepare 80 mL of 0.10 M NH3 from 6.0 M ammonia?
How do I prepare 80 mL of 0.10 M NH3 from 6.0 M ammonia?
Answers
Answered by
DrBob222
How accurately is the acetic acid solution to be made?
mL x M = mL x M
80 mL x 0.1M = mL x 6.0M
mL = (80*0.1/6.0) = 1.33
Technically, the way you do it is to dispense 1.33 mL of the stock solution into an 80 mL volumetric flask, then make the solution to the mark with distilled water. However, I don't know that I've seen an 80 mL volumetric flask.
mL x M = mL x M
80 mL x 0.1M = mL x 6.0M
mL = (80*0.1/6.0) = 1.33
Technically, the way you do it is to dispense 1.33 mL of the stock solution into an 80 mL volumetric flask, then make the solution to the mark with distilled water. However, I don't know that I've seen an 80 mL volumetric flask.
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