Ask a New Question

Question

How would you prepare 385 ml of a 0.856 m NaOH solution starting with a 4.93 m stock solution
10 years ago

Answers

DrBob222
I assume you know the difference between 0.856 m and 0.856 M. Is this really m or should it be M?
10 years ago
Keyera
should be M
10 years ago
DrBob222
That makes it easier.
Use mL1 x M1 = mL2 x M2
385*0856 = mL2 x 4.93
Solve for mL2.

Directions then would be, measure out mL2 volume of 4.93M solution and add enough water to make 385 mL. The final solution will be 0.856 M.
10 years ago

Related Questions

How would you prepare 1L of a .050 M phosphate buffer at pH 7.5 using crystalline K2HPO4 and a solut... How do I prepare 40% v/v from 95% ethanol? When we say 95% ethanol, do we usually mean 95% w/w ethan... How would you usually prepare starch indicator solution for iodine titrations? Can the solution be s... How would you prepare a 250 mL solution of . 45 M from a stock solution of 5.5 M? how would you prepare 60.0 mL of 0.200 M HNO3 from a stock solution of 4.00 M HNO3? You need to prepare 500.00 mL of a 0.25 M solution of nitric acid . Concentrated nitric acid comes f... Why is it necessary to prepare formal financial statements if all of the data are in the statement c... You need to prepare 1.000 L (in a volumetric flask) of 0.50 M phosphate buffer, pH 6.77. Use the Hen... Does anyone know how to prepare for the final exam for Social Civics for American Schools?
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use