Asked by Anna
How would you prepare 165 mL of a 0.976 M NaOH solution, starting with a 6.36 M stock solution?
Volume of solution needed?
Volume of water needed?
Volume of solution needed?
Volume of water needed?
Answers
Answered by
DrBob222
mL1 x M1 = mL2 x M2
165 x 0.976 = mL2 x 6.36
Solve for mL2, place that in a container and add enough water to make 165 mL.
165 x 0.976 = mL2 x 6.36
Solve for mL2, place that in a container and add enough water to make 165 mL.
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