Asked by quincy
find the distance between the two points(7,3)(1,5)and(8,2),(4,1)
Answers
Answered by
Bosnian
d=sqroot[(x2-x1)^2+(y2-y1)^2]
Distance between points(7,3)(1,5)
x1=7 x2=1 y1=3 y2=5
d=sqroot[(1-7)^2+(5-3)^2]
d=sqroot[(-6)^2+2^2]
d=sqroot(36+4)
d=sqroot(40)
Distance between points(8,2)(4,1)
x1=8 x2=4 y1=2 y2=1
d=sqroot[(8-4)^2+(1-2)^2]
d=sqroot[(4)^2+(-1)^2]
d=sqroot(16+1)
d=sqroot(17)
In google type: points distance
When you see list of results click some link
Distance between points(7,3)(1,5)
x1=7 x2=1 y1=3 y2=5
d=sqroot[(1-7)^2+(5-3)^2]
d=sqroot[(-6)^2+2^2]
d=sqroot(36+4)
d=sqroot(40)
Distance between points(8,2)(4,1)
x1=8 x2=4 y1=2 y2=1
d=sqroot[(8-4)^2+(1-2)^2]
d=sqroot[(4)^2+(-1)^2]
d=sqroot(16+1)
d=sqroot(17)
In google type: points distance
When you see list of results click some link
Answered by
Bosnian
sqroot(40)=sqroot(4*10)=2*sqroot(10)
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