Question

A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the system is 2.00 J, find
(a) The force constant of the spring and
(b) The amplitude of the motion.

Answer 1

a) T = 2pi / w so w = 2 pi / T

w = sqrt ( k / m )

so k = w² / m

b) (1/2)* k * xmax ² = 2,00 J

so, xmax = sqrt( 2,00 * 2 / k)

Answer 2

Actually for part a it's;

k=w^2*m