Asked by Anonymous
A 6.76 kg block is attached to a spring with spring constant 36.9 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 57 cm/s. What are
The amplitude of the subsequent oscillations?
The amplitude of the subsequent oscillations?
Answers
Answered by
drwls
The kinetic energy given by the blow, (1/2) M V^2, equals the spring potential energy at maximum deflection A:
(1/2) k A^2 = (1/2) M V^2
A = V*sqrt(M/k)
Make sure the V is in m/s
(1/2) k A^2 = (1/2) M V^2
A = V*sqrt(M/k)
Make sure the V is in m/s
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