Asked by quaviz
A 5.7 kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t = 0 s, the block has a displacement of -0.70 m, a velocity of -0.80 m/s, and an acceleration of +2.7 m/s2. The amplitude of the motion is closest to:
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Answered by
drwls
If this is multiple choice, please provide the choices.
The problem can be solved by recalling that the sum of potential energy and kinetic energy is constant. The constant will equal k A^2, where A is the amplitude. The t=0 acceleration can be used to get the spring constant k, which you will need for the t=0 potential energy.
The problem can be solved by recalling that the sum of potential energy and kinetic energy is constant. The constant will equal k A^2, where A is the amplitude. The t=0 acceleration can be used to get the spring constant k, which you will need for the t=0 potential energy.
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