rearrange things a bit to get
x-3y=5
3x-5y=7
If you multiply the 1st equation by 3, you have
3x-9y=15
3x-5y=7
Now just subtract to eliminate x and you get
-4y = 8
y = -2
Now use either equation to solve for x.
4x-3y=5
Solve {
5y+7=3x
using the method of elimination.
2 answers
Had that first equation not mysteriously changed we would have;
1st times 3 ---> 12x - 9y = 15
2nd times 4 ---> 12 - 20y = 28
subtract:
11y = -13
y = -13/11
into 1st:
4x -3(-13/11) = 5
4x = 5 - 39/11 = 16/11
x = 4/11
1st times 3 ---> 12x - 9y = 15
2nd times 4 ---> 12 - 20y = 28
subtract:
11y = -13
y = -13/11
into 1st:
4x -3(-13/11) = 5
4x = 5 - 39/11 = 16/11
x = 4/11
1 answer