4x-3y=5

Solve {
5y+7=3x

using the method of elimination.

2 answers

rearrange things a bit to get

x-3y=5
3x-5y=7

If you multiply the 1st equation by 3, you have

3x-9y=15
3x-5y=7

Now just subtract to eliminate x and you get

-4y = 8
y = -2

Now use either equation to solve for x.
Had that first equation not mysteriously changed we would have;

1st times 3 ---> 12x - 9y = 15
2nd times 4 ---> 12 - 20y = 28
subtract:
11y = -13
y = -13/11

into 1st:
4x -3(-13/11) = 5
4x = 5 - 39/11 = 16/11
x = 4/11
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