4tan^2u-1=tan^2u

Question

3tan^2u=1

tan^2u=1/3

sq. root of (tan^2u)=sq. root of (1/3)

tanu=sq. root of (3)/3

tanu=sq. root of 1

Did I do this one right? If not, could you please show me the correct method??
Thanks!

Answer 1

I don't understand your last step.
From tanu=sq. root of (3)/3
The next step would be
u = tan^-1[1/(sqrt3)]= 30 degrees
(or 210 degrees)

Your first steps are OK, until the last line.