4tan^2u-1=tan^2u 3tan^2u=1 tan^2u=1/3 sq. root

  1. 4tan^2u-1=tan^2u3tan^2u=1 tan^2u=1/3 sq. root of (tan^2u)=sq. root of (1/3) tanu=sq. root of (3)/3 tanu=sq. root of 1 Did I do
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    2. Tara asked by Tara
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  2. i)The angle á lies between 0 and 90 and is such that 2tan sqaure á + sec square á=5-4tan á. show that3tan square á
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  3. Solve: 3tan^2x-1=0. I got +/- (the sq. root of 3)/3 which is correct according to my study guide. However, I don't know how to
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  4. 1/4tan(2x)
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  5. solve the equation 3=4tan(2x+Pi/6) for x
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  7. Simplify:2sec^2A-2/4tan A...Please help,anyone who can answer
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  8. if cosA= -1/2 and π<A<3π/2 then find the value of 4tan^2A-3cosec^2A ?
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  10. find y' of the functuion in terms of appropriate variable. simplify as far as possible.y= 1+5^x^2-4tan(3x)
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    2. nicole asked by nicole
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