4FeS (s) + 7O2 (g) --> 2Fe2O3 (s) + 4SO2 (g)

Entropy value for iron (II) sulfide is 67 J/K mol
I don't understand how to find entropy

1 answer

Do you want the entropy of the reaction?
dSrxn = (n*dSo products) - (n*dSo reactants).
Look up the standard S values in your text/notes and plug into the above equation and solve for dSrxn.