In the following reaction, how many grams of ferrous sulfide (FeS) will produce 0.56 grams of iron (III) oxide (Fe2O3)?

4FeS + 7O2 d 2Fe2O3 + 4SO2

The molar mass of ferrous sulfide is 87.92 grams and that of iron (III) oxide is 159.7 grams.

1 answer

mols Fe2O3 desired = grams/molar mass
Convert mols Fe2O3 to mols FeS using the coefficients in the balanced equation.
g FeS = mols FeS x molar mass FeS