Asked by kerin
In the following reaction, how many grams of ferrous sulfide (FeS) will produce 0.56 grams of iron (III) oxide (Fe2O3)?
4FeS + 7O2 d 2Fe2O3 + 4SO2
The molar mass of ferrous sulfide is 87.92 grams and that of iron (III) oxide is 159.7 grams.
4FeS + 7O2 d 2Fe2O3 + 4SO2
The molar mass of ferrous sulfide is 87.92 grams and that of iron (III) oxide is 159.7 grams.
Answers
Answered by
DrBob222
mols Fe2O3 desired = grams/molar mass
Convert mols Fe2O3 to mols FeS using the coefficients in the balanced equation.
g FeS = mols FeS x molar mass FeS
Convert mols Fe2O3 to mols FeS using the coefficients in the balanced equation.
g FeS = mols FeS x molar mass FeS
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