Asked by bri
In the following reaction, how many grams of ferrous sulfide (FeS) will produce 0.56 grams of iron (III) oxide (Fe2O3)?
4FeS + 7O2 d 2Fe2O3 + 4SO2
4FeS + 7O2 d 2Fe2O3 + 4SO2
Answers
Answered by
Steve
.56g of Fe2O3 = .56/159.69 = 0.0035 moles
.0035 moles FeS = 0.307g FeS
.0035 moles FeS = 0.307g FeS
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