In the following reaction, how many grams of ferrous sulfide (FeS) will produce 0.56 grams of iron (III) oxide (Fe2O3)?

Question

4FeS + 7O2 d 2Fe2O3 + 4SO2

Answer 1

.56g of Fe2O3 = .56/159.69 = 0.0035 moles
.0035 moles FeS = 0.307g FeS