Asked by Sidney

Solve for x:
[Sixth root of 27]+[cube root of x] = 6/(3-[square root of 3]
Answered by Reiny
27^(1/6) + x^(1/3) = 6/(3 - √3)

(3^3)^(1/6) + x^(1/3) = 6/(3 - √3)[(3+√3)/(3+√3)]
3^(1/2) + x^(1/3) = 3 + 2√3
x^(1/3) = 3 + √3)

x = (3+√3)^3