Ask a New Question
Search
Asked by
Steve
Solve for x sq root 2x+3= sq root 6x-1
a-1
b-2
c-3
dsq root 6
My answer is a = 1
Answers
Answers
Answered by
Steve
x=1 does satisfy the equation.
Related Questions
Related
Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r squared h / 3 Solv...
Solve by using the even-root property. x^2 = 20
how to solve the square root of 15.59
Solve for x: [Sixth root of 27]+[cube root of x] = 6/(3-[square root of 3]
solve for d. sq root d^2-11=5 A. 4,-4 B. 5,-5 C. 5,6 D. 6,-6 I think it is A....?
Solve square root of 79-5x =6x+4 (Keep your answers in simplified improper fraction form)
solve square root 2x-5 =7 the 2x -5 is under the sqaure
solve square root 5-2x + 5 =12 5-2x under the sqaure
solve 3 square root 2x +1 =3 2x +1 under the sqaure
Solve Root(18+2root65) + root(36+2 root15)=?