Asked by Jamie
                solve: sec(1/4)X+"Square Root of 2"=0
            
            
        Answers
                    Answered by
            Nolan
            
    Simple equation :
X = -sqrt(2)/sec(1/4)
= -sqrt(2)*cos(1/4)
It's not a round value.
    
X = -sqrt(2)/sec(1/4)
= -sqrt(2)*cos(1/4)
It's not a round value.
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