Asked by Jamie
solve: sec(1/4)X+"Square Root of 2"=0
Answers
Answered by
Nolan
Simple equation :
X = -sqrt(2)/sec(1/4)
= -sqrt(2)*cos(1/4)
It's not a round value.
X = -sqrt(2)/sec(1/4)
= -sqrt(2)*cos(1/4)
It's not a round value.
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