Asked by robin
solve using the square root formula
2(x-4)^2+1=17
2(x-4)^2+1=17
Answers
Answered by
oobleck
Not sure just what your formula is, but
2(x-4)^2+1=17
2(x-4)^2=16
(x-4)^2 = 8
x-4 = ±√8
x = 4±√8
2(x-4)^2+1=17
2(x-4)^2=16
(x-4)^2 = 8
x-4 = ±√8
x = 4±√8
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