Asked by Zach
                solve
3 square root 2x +1 =3
2x +1 under the sqaure
            
        3 square root 2x +1 =3
2x +1 under the sqaure
Answers
                    Answered by
            Bosnian
            
    3 square root( 2 x + 1 ) = 3 square both sides
3 ^ 2 * square root( 2 x + 1 ) ^ 2 = 3 ^ 2
9 * ( 2 x + 1 ) ^ 2 = 9 Divide both sides by 9
2 x + 1 = 1 Subtract 1 to both sides
2 x + 1 - 1 = 1 - 1
2 x = 0 Divide both sides by 2
x = 0
    
3 ^ 2 * square root( 2 x + 1 ) ^ 2 = 3 ^ 2
9 * ( 2 x + 1 ) ^ 2 = 9 Divide both sides by 9
2 x + 1 = 1 Subtract 1 to both sides
2 x + 1 - 1 = 1 - 1
2 x = 0 Divide both sides by 2
x = 0
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