Asked by tahj

find the length width and area of an object where the perimeter is fixed at 20 meters
Answered by Ms. Sue
What kind of object?

Answered by tahj
a rectangle
Answered by Ms. Sue
P = 2L + 2W

30 = 2(5) + 2(5)
or
20 = 2(4) + 2(6)
or
20 = 2(3) + 2(7)
or
20 = 2(2) + 2(8)
or
20 = 2(1) + 2(9)
Answered by Ms. Sue
Correction:

the first combination should be:

<b>20</b> = 2(5) + 2(5)
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