Asked by Sam
Find the length and width of a rectangle with maximum area that has a perimeter of (7P) units.
units (smaller value)
units (larger value)
units (smaller value)
units (larger value)
Answers
Answered by
bobpursley
area=Lw
perimeter=2L+2W
area=LW
7P=2L+2W
L=7P/2-W
area=W(7P/2-W)
d area/dw=0=7P/2-2W
W=7P/4
then L=7P/2-7P/4=7P/4
areamax=Lw=7P/4 ^2=49P^2/16
perimeter=2L+2W
area=LW
7P=2L+2W
L=7P/2-W
area=W(7P/2-W)
d area/dw=0=7P/2-2W
W=7P/4
then L=7P/2-7P/4=7P/4
areamax=Lw=7P/4 ^2=49P^2/16
Answered by
anon win
don't know why theres two dislikes, Just did his method and hes right. Good stuff bob.
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